Home O level Computer science O level Computer science Pre release Material 2018

O level Computer science Pre release Material 2018

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O level computer sciecne Pre release material solution

Pre release Material 2018

In preparation for the examination candidates should attempt the following practical tasks by writing and testing a program or programs.
A farmer records the milk production of a herd of cows. Every cow has a unique 3-digit identity code.
Each cow can be milked twice a day, seven days a week. The volume of the milk from each cow is recorded in liters correct to one decimal place (yield) every time the cow is milked. The size of the herd is fixed. At the end of the week the total and the average yield for each cow for the week is calculated.
The farmer identifies the cow that has produced the most milk that week. The farmer also identifies any cows that have produced less than 12 liters of milk on four or more days that week.
A program is required to record the yield for each cow every time it is milked, calculate the total weekly volume of milk for the herd and the average yield per cow in a week. The program must also identify the cow with the best yield that week and identify any cow with a yield of less than 12 liters of milk for four or more days that week.

Write and test a program or programs for the farmer.Your program of programs must include the appropriate prompts for the entry of data.

  • Error messages and other output need to be set out clearly and understandably.
  • All variables, constants and other identifiers must have meaningful names
  • You will need to complete these three tasks. Each task must be fully tested.

TASK 1 – Record the yield

Write a program for TASK 1 to record the milk yields for a week. The program records and stores theidentify code number and the yield every time a cow is milked.

TASK 2 – Calculate the statistics

Using your recorded data from TASK 1, calculate and display the total weekly volume of milk for the herd to nearest while liter. Calculate and display the average yield per cow in a week to the nearest whole liter.ico calendar

TASK 3 – Identify the most productive and cows that are producing a low volume of milk.
Extend TASK 2 to identify and display the identity code number and weekly yield of the cow that has produced the most milk. Also identify and display the identity code numbers of any cows with a yield of less than 12 liters of milk for four days or more in the week.

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Visual Basic (Forms base) Solution

Task1 

Dim nofcows, cowid As Integer
Dim morning, evening, weektotalcow As Single
nofcows = InputBox("How many cows in a herd ? ")
Dim cowids(0 To nofcows) As Integer
Dim milkstore(0 To nofcows) As Single
For cows = 1 To nofcows
	cowid = InputBox(" Enter cow ID ")
	While cowid < 100 Or cowid > 999
		MsgBox(" You have entred the wrong ID. Enter 3 number code. ")
		cowid = InputBox(" Enter cow ID ")
		End While
		cowids(cows) = cowid
	Next
	For cows = 1 To nofcows
		MsgBox(" Enter Milk Yield for cow ID no : " & cowids(cows))
		For days = 1 To 7
			MsgBox(" For day : " & days)
			morning = InputBox(" Morning Yield in liters for cow ")
			evening = InputBox(" Evening Yield in liters for cow ")
			weektotalcow = weektotalcow + morning + evening
		Next
		milkstore(cows) = weektotalcow
	Next


Task 2

Dim total_yield, avg_yield As Single
For cows = 1 To nofcows
	avg_yield = milkstore(cows) / nofcows
	MsgBox(" The average Yield of cow ID no " & cowids(cows) & " is : " &
	Math.Round(avg_yield))
	total_yield = total_yield + milkstore(cows)
Next
MsgBox(" The total weekly volume of milk for the herd : " &
Math.Round(total_yield))


Task 3


Dim highest_yeild As Single
Dim highest_ID As Integer
highest_yeild = 0
For cows = 1 To nofcows
	If milkstore(cows) > highest_yeild Then
		highest_yeild = milkstore(cows)
		highest_ID = cowids(cows)
		End IfPre Release Material CS 2210 O Levels Summers 2018
		A Project Of csmeasy.com
	Next
	MsgBox(" The Cow ID no : " & highest_ID & " has produced the highest yeild " &
	highest_yeild)
	For cows = 1 To nofcows
		If milkstore(cows) < 12.0 Then
			MsgBox(" The cow ID no " & cowids(cows) & " has produced less then 12
			Liters In a week")
		End If
	Next
End Sub
End Class


Credits to : Engr. Bandeshah for the Visual Basic Solution

Python Solution

Task 1


#Recording the yield
Cow = []
Yield = []

Cows = int(input("How many cows are in the herd?  "))
Day = 0     #to configure the milking
for i in range(14):
    if i%2 == 1:
        Milking = "Second"
    else:
        Milking = "First"
        Day += 1
    print("Day ", Day, "; ", Milking, " milking")
    for i in range(Cows):
        while True:
            Code = int(input("Enter code: "))
            if Code > 999 or Code < 100:
                print("Enter a 3-digit code please")
            else:
                Cow.append(Code)
                break
        Y = float(input("Enter volume of milk in litres: "))    #A range check for yield can be added 
        Yield.append(Y)

Task 2


#Finding the Total and Average
Total = 0
for i in range(len(Yield)):
    Total += Yield[i]
Average = Total/Cows

round(Total, 0)
round(Average, 0)

print("Total weekly volume of milk: ", int(Total), " litres")
print("Average yield per cow: ", int(Average), " litres")

Task 3


#Identifying most productive and low producing cows
Total = []
LessMilk = ""
YieldOnDay = 0
Milking = 0
for j in range(Cows):
    T = 0
    Days = 0
    Cow = Cow[j]                    #A cow chosen 
    for i in range(len(Cow)):
        if Cow[i] == Cow:
            T += Yield[i]         #Incrementing the total for each cow 
            YieldOnDay += Yield[i]
            Milking += 1
            if Milking == 2:            # 2 since checking for days, not milkings
                if YieldOnDay < 12: #Checking if yield is less than 12 Days += 1 Milking = 0 YieldOnDay = 0 if Days > 3:        #Low yield for 4 or more days 
        LessMilk = LessMilk + str(Cow[j]) + ", "
    Total.append(T)

print(Total)
for i in range(Cows):
    if Total[i] == max(Total):
        print("Cow ", Cow[i], " has the highest yield of ", Total[i], " litres")

print("Cows which produced less than 12 litres of milk: " , LessMilk)

14 COMMENTS

  1. The task 3 specifically states “identify and display the identity code numbers of any cows with a yield of less than 12 liters of milk **for four days or more** in the week”. Your variable “milkstore” stores the total weekly volume of milk yield from each cow so how can this requirement of the task be satisfied by this statement of your program: “If milkstore(cows) < 12.0 ….."
    ????

  2. avg_yield = milkstore(cows) / nofcows

    This statement seems to me incorrect. Here we are dividing 1 cow yield by noofcows which seems incorrect. It should be either noofdays(7) or we have complete total of milk yield for all the cows. These are my suggestions.

  3. It says the size of the herd if fixed, still your asking to input the size of the herd (I think this is a constant candidate). Furthermore, the three digit check is wrong, what if the three digit is 000 or 099?

  4. Good Job but one point is not considered here which is very important for marks. “for 4 or more days”
    there should be counter for those days.

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